JEE Main 2020 — Binomial Theorem Question with Solution
From: JEE Main 2020 (Online) 5th September Evening Slot
Question
The coefficient of x4
in the expansion of
(1 + x + x2 + x3)6 in powers of x, is ______.
(1 + x + x2 + x3)6 in powers of x, is ______.
Enter your answer
Show full solutionCorrect answer: 120
Correct answer
120
Step-by-step explanation
(1 + x + x2
+ x3)6
= ((1 + x) (1 + x2))6
= (1 + x)6(1 + x2)6
=
Coefficient of x4 = 6C0 6C2 + 6C2 6C1 + 6C4 6C0 = 120
= ((1 + x) (1 + x2))6
= (1 + x)6(1 + x2)6
=
Coefficient of x4 = 6C0 6C2 + 6C2 6C1 + 6C4 6C0 = 120
Practice this on the real CBT interface
Solve this JEE Main question (and the rest of the Binomial Theorem chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.
Solve interactively →About this question
This is a previous-year question from JEE Main 2020, covering the Binomial Theorem chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.