JEE Main 2021 — Binomial Theorem Question with Solution
From: JEE Main 2021 (Online) 18th March Morning Shift
Question
Let (1 + x + 2x2)20 = a0 + a1x + a2x2 + .... + a40x40. Then a1 + a3 + a5 + ..... + a37 is equal to
Choose an option
Show full solutionCorrect option: B
Correct answer
B219(220 21)
Step-by-step explanation
Put x = 1
..... (i)
Put x = 1
..... (ii)
by (i) (ii) we get,
..... (iii)
a39 = coeff. x39 in (1 + x + 2x2)20
Practice this on the real CBT interface
Solve this JEE Main question (and the rest of the Binomial Theorem chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.
Solve interactively →About this question
This is a previous-year question from JEE Main 2021, covering the Binomial Theorem chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.