JEE Main 2020 — Binomial Theorem Question with Solution
From: JEE Main 2020 (Online) 2nd September Morning Slot
Question
Let
> 0,
> 0 be such that
3 + 2 = 4. If the maximum value of the term independent of x in
the binomial expansion of is 10k,
then k is equal to :
3 + 2 = 4. If the maximum value of the term independent of x in
the binomial expansion of is 10k,
then k is equal to :
Choose an option
Show full solutionCorrect option: B
Correct answer
B336
Step-by-step explanation
General term
Tr + 1 = 10Cr
= 10Cr
If Tr + 1 is independent of x
= 0
r = 4
T5 = 10C4
Also given, 3 + 2 = 4
By AM-GM inequality
(2)2
16
10k = 10C4 (16)
k = 336
Tr + 1 = 10Cr
= 10Cr
If Tr + 1 is independent of x
= 0
r = 4
T5 = 10C4
Also given, 3 + 2 = 4
By AM-GM inequality
(2)2
16
10k = 10C4 (16)
k = 336
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