JEE Main 2024MathematicsCircleEasyMCQ

JEE Main 2024 — Circle Question with Solution

JEE Main 2024 (27 Jan Shift 1)

Question

Four distinct points (2k,3k),(1,0),(0,1) and (0,0) lie on a circle for k equal to :

Choose an option

Show full solutionCorrect option: C
Correct answer
C513

Step-by-step explanation

We know that, (1,0), (0,1), (0,0) lies on X-axis, Y-axis and on the origin respectively.

So, (2k,3k) will lie on circle whose diameter is AB.

Equation of the circle will be given by,

⇒(x-1)(x)+(y-1)(y)=0

⇒x2+y2-x-y=0   ...i

Using (2k, 3k) in equation i,

⇒(2k)2+(3k)2-2k-3k=0

⇒13k2-5k=0

⇒k=0, k=513

Hence, k=513.

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About this question

This is a previous-year question from JEE Main 2024, covering the Circle chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.