JEE Main 2016MathematicsCircleMediumMCQ

JEE Main 2016Circle Question with Solution

JEE Main 2016 (03 Apr)

Question

If one of the diameters of the circle, given by the equation, x2+y2-4x+6y-12=0, is a chord of a circle S, whose centre is at -3, 2, then the radius of S is

Choose an option

Show full solutionCorrect option: D
Correct answer
D53

Step-by-step explanation

The centre of the given circle x2+y2-4x+6y-12=0 is 2, -3 and the radius is 5.

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The distance between the centres 52 and radius is 5. The triangle OPQ is a right angled triangle

OQ= 522+52= 532=53

Hence answer is 53

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About this question

This is a previous-year question from JEE Main 2016, covering the Circle chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.