JEE Main 2016 — Circle Question with Solution
From: JEE Main 2016 (Online) 10th April Morning Slot
Question
Equation of the tangent to the circle, at the point (1, −1), whose centre is the point of intersection of the straight lines x − y = 1 and 2x + y = 3 is :
Choose an option
Show full solutionCorrect option: B
Correct answer
Bx + 4y + 3 = 0
Step-by-step explanation
Point of intersection of lines
x y = 1 and 2x + y = 3 is
Slope of OP = = = 4
Slope of tangent =
Equation of tangent y + 1 = (x 1)
4y + 4 = x + 1
x + 4y + 3 = 0
x y = 1 and 2x + y = 3 is
Slope of OP = = = 4
Slope of tangent =
Equation of tangent y + 1 = (x 1)
4y + 4 = x + 1
x + 4y + 3 = 0
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