JEE Main 2020MathematicsCircleMediumMCQ

JEE Main 2020 — Circle Question with Solution

JEE Main 2020 (08 Jan Shift 2)

Question

If a line y=mx+c, is a tangent to the circle x-32+y2=1, and it is perpendicular to a line L1, where L1 is the tangent to the circle x2+y2=1, at the point 12, 12, then

Choose an option

Show full solutionCorrect option: C
Correct answer
Cc2+6c+7=0

Step-by-step explanation

Slope of tangent to x2+y2=1 at 12,12
x2+y2=1
2x+2yy'=0
y'=-xy=-1
Given that, y=mx+c, is perpendicular to L1,
So, m=1 ⇒y=x+c

Now distance of 3,0 from y=x+c is
c+32=1
c2+6c+9=2
c2+6c+7=0.

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About this question

This is a previous-year question from JEE Main 2020, covering the Circle chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.