JEE Main 2022MathematicsComplex NumberEasyMCQ

JEE Main 2022 — Complex Number Question with Solution

JEE Main 2022 (29 Jun Shift 1)

Question

Let α and β be the roots of the equation x2+2i-1=0. Then, the value of α8+β8 is equal to

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Show full solutionCorrect option: A
Correct answer
A50

Step-by-step explanation

Since α and β are the roots of the equation x2+2i-1=0

so α2=-2i+1=β2

⇒α4=-2i+12=4i2+1-4i=-3-4i

⇒α8=-3-4i2=-7+24i

Similarly, β8=-7+24i

∴α8+β8=-14+48i=50

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About this question

This is a previous-year question from JEE Main 2022, covering the Complex Number chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.