JEE Main 2017MathematicsComplex NumberHardMCQ

JEE Main 2017 — Complex Number Question with Solution

JEE Main 2017 (02 Apr)

Question

Let ω be a complex number such that 2ω+1=z where z=-3 . If

1111-ω2-1ω21ω2ω7=3k,

Then k can be equal to:

Choose an option

Show full solutionCorrect option: A
Correct answer
A–z

Step-by-step explanation

ω= -12+32 i (cube root of unity)

So, 1+ω+ω2=0  and  ω3=1

Now 1111ωω21ω2ω=3ω2-ω

So k=ω2-ω

⇒k=-12-32i--12+32i

⇒k=-3i

⇒k=-z

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About this question

This is a previous-year question from JEE Main 2017, covering the Complex Number chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.