JEE Main 2014MathematicsComplex NumberMediumMCQ

JEE Main 2014 — Complex Number Question with Solution

JEE Main 2014 (06 Apr)

Question

If z is a complex number such that z≥2, then the minimum value of z+12 :

Choose an option

Show full solutionCorrect option: D
Correct answer
DLies in the interval (1, 2)

Step-by-step explanation

z≥2  i.e.,  z-0≥2

∴  The distance of 'z' from origin is greater than two.
We have to find minimum of z+12

z+12=z--12 = distance of z from -12, 0.

On the argand plane,



z lies in the dotted regions I, II, III, IV.

∴    The minimum distance is from the point B=2-12 = 3 2

⇒32∈1, 2

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About this question

This is a previous-year question from JEE Main 2014, covering the Complex Number chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.