JEE Main 2019MathematicsContinuity and DifferentiabilityMediumMCQ

JEE Main 2019 — Continuity and Differentiability Question with Solution

JEE Main 2019 (10 Jan Shift 1)

Question

Let fx=maxx, x2,x≤28-2x,2<x≤4. Let S be the set of points in the interval -4, 4 at which f is not differentiable. Then S

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Show full solutionCorrect option: A
Correct answer
Aequals -2, -1, 0, 1, 2

Step-by-step explanation

Given function is fx=maxx, x2,x≤28-2x,2<x≤4

The graph of the function, is

We know that, a function is not differentiable at a point where its graph has a sharp corner.

And, from the graph we can easily conclude that fx is non-derivable at x=-2, -1, 0,1, 2

Hence, the set S=-2, -1, 0,1, 2.

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About this question

This is a previous-year question from JEE Main 2019, covering the Continuity and Differentiability chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.