JEE Main 2019MathematicsContinuity and DifferentiabilityEasyMCQ

JEE Main 2019 — Continuity and Differentiability Question with Solution

JEE Main 2019 (09 Apr Shift 2)

Question

If the function fx=aπ-x+1,  x≤5bx-π+3,  x>5 is continuous at x=5, then the value of a-b is:

Choose an option

Show full solutionCorrect option: A
Correct answer
A25-π

Step-by-step explanation

For continuity at x=5

limx→5+fx=limx→5-fx=f5

⇒limx→5+bx-π+3=limx→5-aπ-x+1=a5-π+1

We know that x=   x,x≥0-x,x<0

⇒b5-π+3=a5-π+1=a5-π+1

⇒b5-π+3=a5-π+1

⇒3-1=a5-π-b5-π

⇒a-b5-π=2

⇒a-b=25-π.

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About this question

This is a previous-year question from JEE Main 2019, covering the Continuity and Differentiability chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.