JEE Main 2024 — Continuity and Differentiability Question with Solution
JEE Main 2024 (04 Apr Shift 1)
Question
Let be a function given by
$f(x)=\left\{\begin{array}{ll}
\frac{1-\cos 2 x}{x^2}, & x < 0 \\
\alpha, & x=0, \\
\frac{\beta \sqrt{1-\cos x}}{x}, & x>0
\end{array}\right.$
where . If is continuous at , then is equal to :
Choose an option
Show full solutionCorrect option: B
Correct answer
B12
Step-by-step explanation
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This is a previous-year question from JEE Main 2024, covering the Continuity and Differentiability chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.