JEE Main 2020MathematicsContinuity and DifferentiabilityMediumNumerical

JEE Main 2020Continuity and Differentiability Question with Solution

JEE Main 2020 (07 Jan Shift 1)

Question

Let S be the set of points where the function ,fx=|2-|x-3|,xR, is not differentiable. Then xSffx is equal to

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Show full solutionCorrect answer: 3
Correct answer
3

Step-by-step explanation

Check non-differentiability of function, we get,

fx is non differentiable at x=1,3,5
ffx=ff1+ff3+ff5
=1+1+1
=3

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About this question

This is a previous-year question from JEE Main 2020, covering the Continuity and Differentiability chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.