JEE Main 2020MathematicsContinuity and DifferentiabilityHardMCQ

JEE Main 2020 — Continuity and Differentiability Question with Solution

JEE Main 2020 (04 Sep Shift 2)

Question

The function fx=π4+tan-1x,x≤112x-1,x>1 is :

Choose an option

Show full solutionCorrect option: A
Correct answer
Acontinuous on R-1 and differentiable on R--1,1.

Step-by-step explanation

fx=π4+tan-1x,x≤112x-1,x>1

Making graph

Clearly, function is continuous on R–1 and differentiable on R––1,1.

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About this question

This is a previous-year question from JEE Main 2020, covering the Continuity and Differentiability chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.