JEE Main 2017MathematicsContinuity and DifferentiabilityEasyMCQ

JEE Main 2017 — Continuity and Differentiability Question with Solution

JEE Main 2017 (09 Apr Online)

Question

The value of k which the function fx= 45tan⁡4xtan⁡5x,0<x<π2k+25,x=π2 is continuous at x=π2, is

Choose an option

Show full solutionCorrect option: D
Correct answer
D35

Step-by-step explanation

Given function is continuous at x= π 2

⇒fπ2=fπ+2=fπ-2 

⇒k+25=45tan⁡4xtan⁡5x

⇒k+25=45tan2πcot5π2

⇒k+25=450  

⇒k+25=1   

⇒k=35

Practice this on the real CBT interface

Solve this JEE Main question (and the rest of the Continuity and Differentiability chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.

Solve interactively →

About this question

This is a previous-year question from JEE Main 2017, covering the Continuity and Differentiability chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.