JEE Main 2022MathematicsDefinite IntegrationMediumMCQ

JEE Main 2022Definite Integration Question with Solution

JEE Main 2022 (26 Jul Shift 1)

Question

If a=limnk=1n2nn2+k2 and fx=1-cosx1+cosx,x0,1, then:

Choose an option

Show full solutionCorrect option: C
Correct answer
C2fa2=f'a2

Step-by-step explanation

Given, a=limnk=1n2nn2+k2

a=1nk=1n21+kn2=0121+x2dx

a=2tan-1x01

a=2π4-0=π2

Now, fx=1-cosx1+cosx

fx=tanx2;x0,1

So, fa2=fπ4

fπ4=2-1

And f'π4=12sec2π8=22+1

So, f'π4=2fπ4

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About this question

This is a previous-year question from JEE Main 2022, covering the Definite Integration chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.