JEE Main 2020MathematicsDefinite IntegrationHardMCQ

JEE Main 2020 — Definite Integration Question with Solution

JEE Main 2020 (08 Jan Shift 2)

Question

If I=∫12dx2x3-9x2+12x+4, then

Choose an option

Show full solutionCorrect option: B
Correct answer
B19<I2<18

Step-by-step explanation

fx=12x3-9x2+12x+4
f'x=-126x2-18x+122x3-9x2+12x+432

f'x=-6x-1x-222x3-9x2+12x+432

f'x=0 ⇒x=1, 2
f1=13 , f2=18

13<fx<18

⇒∫1213dx<∫12fxdx<∫1218dx
⇒13<I<18 

⇒19<I2<18.

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About this question

This is a previous-year question from JEE Main 2020, covering the Definite Integration chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.