JEE Main 2020MathematicsDefinite IntegrationHardNumerical

JEE Main 2020 — Definite Integration Question with Solution

JEE Main 2020 (02 Sep Shift 1)

Question

The integral ∫02x-1-xdx is equal to

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Show full solutionCorrect answer: 1.5
Correct answer
1.5

Step-by-step explanation

∫02x-1-xdx=∫011-x-xdx+∫12x-1-xdx

=∫0121-2xdx+∫1212x-1dx+∫12dx

=x-x2012+x2-x121+x12=12-14-0-0+1-1-14-12+2-1

=14+14+1=32=1.5

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About this question

This is a previous-year question from JEE Main 2020, covering the Definite Integration chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.