JEE Main 2018MathematicsDeterminantsEasyMCQ

JEE Main 2018 — Determinants Question with Solution

JEE Main 2018 (16 Apr Online)

Question

The number of values of k for which the system of linear equations k+2x+10y=k & kx+k+3y=k-1 has no solution is

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Show full solutionCorrect option: A
Correct answer
A1

Step-by-step explanation

For no solution

k+2k=10k+3=kk-1

⇒k+2k+3=10k

⇒k2-5k+6=0⇒k=2, 3

k≠2 for k=2 both lines are identical.

So, only k=3 is possible.

So the number of values of k is 1.

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About this question

This is a previous-year question from JEE Main 2018, covering the Determinants chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.