JEE Main 2017MathematicsDeterminantsMediumMCQ

JEE Main 2017Determinants Question with Solution

JEE Main 2017 (08 Apr Online)

Question

If S=x0, 2π :0cosx-sinxsinx0cosxcosxsinx0=0,  then xStanπ3+x is equal to:

Choose an option

Show full solutionCorrect option: B
Correct answer
B-4-23

Step-by-step explanation

Given,0cosx-sinxsinx0cosxcosxsinx0=0

Expanding the determinant,

0(0-cosxsinx)-cosx0-cos2x-sinxsin2x-0=0

cos3x-sin3x=0

tan3x=1 tanx=1x=π4,5π4  S=π4, 5π4

xStanπ3+x

=xS3+tanx13tanx

=23+11-3=-4-23

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About this question

This is a previous-year question from JEE Main 2017, covering the Determinants chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.