JEE Main 2017MathematicsDifferential EquationsMediumMCQ

JEE Main 2017 — Differential Equations Question with Solution

JEE Main 2017 (08 Apr Online)

Question

The curve satisfying the differential equation, ydx-x+3y2dy=0 and passing through the point (1,1) also passes through the point

Choose an option

Show full solutionCorrect option: B
Correct answer
B-13,13

Step-by-step explanation

Given differential equation, ydx-xdy-3y2 dy=0

⇒ dxdy=xy+3y

dxdy-xy=3y

I.F. = e-∫1y dy =e-ln⁡y=1y

∴ solution is

xy= ∫3y .1ydy

⇒ xy=3y+c

Passes through (1,1),

∴  1=3+c ;c=-2

Equation of required curve, x=3y2-2y

Clearly, it passes through −13,13. 

Practice this on the real CBT interface

Solve this JEE Main question (and the rest of the Differential Equations chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.

Solve interactively →

About this question

This is a previous-year question from JEE Main 2017, covering the Differential Equations chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.