JEE Main 2021 — Differential Equations Question with Solution
From: JEE Main 2021 (Online) 26th August Evening Shift
Question
Let y(x) be the solution of the differential equation
2x2 dy + (ey 2x)dx = 0, x > 0. If y(e) = 1, then y(1) is equal to :
2x2 dy + (ey 2x)dx = 0, x > 0. If y(e) = 1, then y(1) is equal to :
Choose an option
Show full solutionCorrect option: C
Correct answer
Cloge 2
Step-by-step explanation
Put
, passes through (e, 1)
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This is a previous-year question from JEE Main 2021, covering the Differential Equations chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.