JEE Main 2019 — Differential Equations Question with Solution
From: JEE Main 2019 (Online) 10th January Evening Slot
Question
The curve amongst the family of curves represented by the differential equation, (x2 – y2)dx + 2xy dy = 0 which passes through (1, 1) is :
Choose an option
Show full solutionCorrect option: C
Correct answer
Ca circle with centre on the x-axis
Step-by-step explanation
(x2 y2) dx + 2xy dy = 0
Put
Solving we get,
ln(v2 + 1) = ln x + C
(y2 + x2) = Cx
1 + 1 = C C = 2
y2 + x2 = 2x
Put
Solving we get,
ln(v2 + 1) = ln x + C
(y2 + x2) = Cx
1 + 1 = C C = 2
y2 + x2 = 2x
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This is a previous-year question from JEE Main 2019, covering the Differential Equations chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.