JEE Main 2020MathematicsDifferential EquationsMediumMCQ

JEE Main 2020 — Differential Equations Question with Solution

JEE Main 2020 (06 Sep Shift 2)

Question

If y=2πx-1cosecx is the solution of the differential equation, dydx+pxy=-2πcosecx, 0<x<π2, then the function px is equal to :

Choose an option

Show full solutionCorrect option: A
Correct answer
Acotx

Step-by-step explanation

y=2πx-1cosec x

⇒dydx=2πcosec x-2xπ-1cosecx cotx cot⁡x

⇒dydx+2xπ-1cosecx cotx=2πcosecx

⇒dydx+ycotx=2πcosecx

⇒px=cotx

Practice this on the real CBT interface

Solve this JEE Main question (and the rest of the Differential Equations chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.

Solve interactively →

About this question

This is a previous-year question from JEE Main 2020, covering the Differential Equations chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.