JEE Main 2018MathematicsDifferential EquationsFormation Of Differential EquationsmediumMCQ

JEE Main 2018Differential Equations Question with Solution

From: JEE Main 2018 (Online) 16th April Morning Slot

Question

The differential equation representing the family of ellipse having foci eith on the x-axis or on the -axis, center at the origin and passing through the point (0, 3) is :

Choose an option

Show full solutionCorrect option: D
Correct answer
Dxy y' y2 + 9 = 0

Step-by-step explanation

Equation of ellipse,



As ellipse passes through (0, 3)



   b2 = 9

Equation of ellipse becomes,



Differentiating w.r.t    x, we get,

+ .

   =

   (1)

We got earlier,

= 1

  

putting value of equation (1) here,



   xyy' + y2 = 9

   xyy' y2 + 9 = 0

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About this question

This is a previous-year question from JEE Main 2018, covering the Differential Equations chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.