JEE Main 2020 — Differential Equations Question with Solution
From: JEE Main 2020 (Online) 5th September Morning Slot
Question
If y = y(x) is the solution of the differential
equation satisfying y(0) = 1, then a value of y(loge13) is :
equation satisfying y(0) = 1, then a value of y(loge13) is :
Choose an option
Show full solutionCorrect option: A
Correct answer
A-1
Step-by-step explanation
Integrating both sides,
ln (y + 2) = – ln(ex + 5) + k
(y + 2) (ex + 5) = C
y(0) = 1
C = 18
y + 2 =
At x = loge13
y + 2 = = 1
y = -1
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