JEE Main 2020 — Differential Equations Question with Solution
From: JEE Main 2020 (Online) 6th September Morning Slot
Question
The general solution of the differential equation
+ xy = 0 is :
(where C is a constant of integration)
+ xy = 0 is :
(where C is a constant of integration)
Choose an option
Show full solutionCorrect option: C
Correct answer
C
Step-by-step explanation
+ xy = 0
+ xy = 0
= -xy
.....(1)
Now put 1 + x2 = u2 and 1 + y2 = v2
2xdx = 2udu and 2ydy = 2vdv
xdx = udu and ydy = vdv
Substitute these values in equation (1)
v =
v = -u - + C
= + + C
+ xy = 0
= -xy
.....(1)
Now put 1 + x2 = u2 and 1 + y2 = v2
2xdx = 2udu and 2ydy = 2vdv
xdx = udu and ydy = vdv
Substitute these values in equation (1)
v =
v = -u - + C
= + + C
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This is a previous-year question from JEE Main 2020, covering the Differential Equations chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.