JEE Main 2017 — Differential Equations Question with Solution
From: JEE Main 2017 (Online) 8th April Morning Slot
Question
The curve satisfying the differential equation, ydx (x + 3y2)dy = 0 and passing through the point (1, 1), also passes through the point :
Choose an option
Show full solutionCorrect option: B
Correct answer
B
Step-by-step explanation
Given,
y dx =
y = x + 3y2
If = = =
Soluation is ,
x . =
= 3y + c
This curve passing through (1, 1)
1 = 3 + c
c = 2
Curve is, x = 3y2 2y
Now put every point in this equation, and see which point satisfy this equation.
Following this method you can see ( , ) point satisfy this equation.
y dx =
y = x + 3y2
If = = =
Soluation is ,
x . =
= 3y + c
This curve passing through (1, 1)
1 = 3 + c
c = 2
Curve is, x = 3y2 2y
Now put every point in this equation, and see which point satisfy this equation.
Following this method you can see ( , ) point satisfy this equation.
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This is a previous-year question from JEE Main 2017, covering the Differential Equations chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.