JEE Main 2021MathematicsDifferential EquationsSolution Of Differential Equations By Method Of Separation Variables And HomogeneoushardMCQ

JEE Main 2021Differential Equations Question with Solution

From: JEE Main 2021 (Online) 16th March Evening Shift

Question

Let C1 be the curve obtained by the solution of differential equation

. Let the curve C2 be the

solution of . If both the curves pass through (1, 1), then the area enclosed by the curves C1 and C2 is equal to :

Choose an option

Show full solutionCorrect option: D
Correct answer
D 1

Step-by-step explanation



Put











It pass through (1, 1)



Similarly for second differential equation

Equation of curve is x2 + y2 2y = 0

Now required area is

JEE Main 2021 (Online) 16th March Evening Shift Mathematics - Differential Equations Question 154 English Explanation



sq. units

Practice this on the real CBT interface

Solve this JEE Main question (and the rest of the Differential Equations chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.

Solve interactively →

About this question

This is a previous-year question from JEE Main 2021, covering the Differential Equations chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.