JEE Main 2020 — Differential Equations Question with Solution
From: JEE Main 2020 (Online) 8th January Evening Slot
Question
The differential equation of the family of
curves, x2 = 4b(y + b), b R, is :
Choose an option
Show full solutionCorrect option: D
Correct answer
Dx(y')2 = x + 2yy'
Step-by-step explanation
x2 = 4b(y + b)
2x = 4by'
b =
differential equation is
x2 = 4.y. + 4
x2 = +
x = +
x(y')2 = x + 2yy'
2x = 4by'
b =
differential equation is
x2 = 4.y. + 4
x2 = +
x = +
x(y')2 = x + 2yy'
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This is a previous-year question from JEE Main 2020, covering the Differential Equations chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.