JEE Main 2020 — Differential Equations Question with Solution
From: JEE Main 2020 (Online) 4th September Morning Slot
Question
Let y = y(x) be the solution of the differential equation,
xy'- y = x2(xcosx + sinx), x > 0. if y () = then
is equal to :
xy'- y = x2(xcosx + sinx), x > 0. if y () = then
is equal to :
Choose an option
Show full solutionCorrect option: C
Correct answer
C
Step-by-step explanation
=
=
x = , y =
= c C = 1
y" =
y"
+ y"
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This is a previous-year question from JEE Main 2020, covering the Differential Equations chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.