JEE Main 2019 — Differential Equations Question with Solution
From: JEE Main 2019 (Online) 12th April Morning Slot
Question
Consider the differential equation, , If value of y is 1 when x = 1, then the value of x
for which y = 2, is :
Choose an option
Show full solutionCorrect option: A
Correct answer
A
Step-by-step explanation
Integrating factor (I.F) =
Now x. = by putting = t
x.et =
It passes through (1, 1)
c =
Equation of the curve is
It passes through (k, 2)
k = = -
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This is a previous-year question from JEE Main 2019, covering the Differential Equations chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.