JEE Main 2019 — Differential Equations Question with Solution
From: JEE Main 2019 (Online) 9th April Morning Slot
Question
The solution of the differential equation
= x2 (x 0) with y(1) = 1, is :
= x2 (x 0) with y(1) = 1, is :
Choose an option
Show full solutionCorrect option: C
Correct answer
C
Step-by-step explanation
= x2
I.F = = x2
The solution is
yx2 =
yx2 = .....(1)
As y(1) = 1
when x = 1 then y = 1.
Putting the value of x and y in equation (1), we get
1 =
C =
Required solution
yx2 =
I.F = = x2
The solution is
yx2 =
yx2 = .....(1)
As y(1) = 1
when x = 1 then y = 1.
Putting the value of x and y in equation (1), we get
1 =
C =
Required solution
yx2 =
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This is a previous-year question from JEE Main 2019, covering the Differential Equations chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.