JEE Main 2020MathematicsDifferential EquationsSolution Of Differential Equations By Method Of Separation Variables And HomogeneousmediumMCQ

JEE Main 2020 — Differential Equations Question with Solution

From: JEE Main 2020 (Online) 7th January Evening Slot

Question

Let y = y(x) be the solution curve of the differential equation,

, satisfying y(0) = 1. This curve intersects the x-axis at a point whose abscissa is :

Choose an option

Show full solutionCorrect option: D
Correct answer
D2 - e

Step-by-step explanation



+ x = y2

I.F = = ey

Solution is given by

xey =

xey = (y2 – 2y + 2)ey + C

y(0) = 1 means x = 0, y = 1

C = -e

xey = (y2 – 2y + 2)ey - e

put y = 0

x = 0 – 0 + 2 – e

x = 2 - e

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About this question

This is a previous-year question from JEE Main 2020, covering the Differential Equations chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.