JEE Main 2020 — Differential Equations Question with Solution
From: JEE Main 2020 (Online) 3rd September Morning Slot
Question
The solution curve of the differential equation,
(1 + e-x)(1 + y2) = y2,
which passes through the point (0, 1), is :
(1 + e-x)(1 + y2) = y2,
which passes through the point (0, 1), is :
Choose an option
Show full solutionCorrect option: D
Correct answer
Dy2 = 1 +
Step-by-step explanation
Given (1 + e-x)(1 + y2) = y2
Integrating both sides,
It passes through (0, 1)
c =
Integrating both sides,
It passes through (0, 1)
c =
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This is a previous-year question from JEE Main 2020, covering the Differential Equations chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.