JEE Main 2022MathematicsDifferentiationMediumMCQ

JEE Main 2022 — Differentiation Question with Solution

JEE Main 2022 (26 Jul Shift 2)

Question

The value of loge2ddxlogcosxcosecx at x=π4 is

Choose an option

Show full solutionCorrect option: D
Correct answer
D4

Step-by-step explanation

For loge2ddxlogcosxcosecx

let, y=logcosxcosecx

i.e. y=-lnsinxlncosx

⇒dydx=-cotx·lncosx+tanx·lnsinxlncosx2

Now dydxx=π4=-cotπ4·lncosπ4+tanπ4·lnsinπ4lncosπ42

=4ln2

⇒loge2·4ln2=4

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About this question

This is a previous-year question from JEE Main 2022, covering the Differentiation chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.