JEE Main 2019MathematicsDifferentiationEasyMCQ

JEE Main 2019 — Differentiation Question with Solution

JEE Main 2019 (09 Jan Shift 2)

Question

If x=3 tant and y=3 sect, then the value of d2ydx2 at t=π4, is:

Choose an option

Show full solutionCorrect option: B
Correct answer
B162

Step-by-step explanation

Given x=3tant and y=3sect

⇒dxdt=3sec2t and dydt=3secttant

⇒dydx=dydtdxdt

⇒dydx=sint

⇒d2ydx2=cost·dtdx=cost ·cos2t3=cos3t3

At t=π4

d2ydx2=162

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About this question

This is a previous-year question from JEE Main 2019, covering the Differentiation chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.