JEE Main 2021 — Ellipse Question with Solution
From: JEE Main 2021 (Online) 26th August Morning Shift
Question
On the ellipse let P be a point in the second quadrant such that the tangent at P to the ellipse is perpendicular to the line x + 2y = 0. Let S and S' be the foci of the ellipse and e be its eccentricity. If A is the area of the triangle SPS' then, the value of (5 e2). A is :
Choose an option
Show full solutionCorrect option: A
Correct answer
A6
Step-by-step explanation
Equation of tangent : y = 2x + 6 at P
P(8/3, 2/3)
S & S' = (2, 0) & (2, 0)
Area of SPS' =
A =
(5 e2)A = = 6
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This is a previous-year question from JEE Main 2021, covering the Ellipse chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.