JEE Main 2025MathematicsEllipseMediumMCQ

JEE Main 2025Ellipse Question with Solution

JEE Main 2025 (23 Jan Shift 2)

Question

The length of the chord of the ellipse , whose mid-point is , is :

Choose an option

Show full solutionCorrect option: C
Correct answer
C

Step-by-step explanation

$\begin{aligned} & T=S_1 \\ & \frac{x \cdot 1}{4}+\frac{y}{4}=\frac{1}{4}+\frac{1}{8} \\ & \Rightarrow 2 x+2 y=3 \\ & \frac{x^2}{4}+\frac{\left(\frac{3-2 x}{2}\right)^2}{2}=1 \\ & \Rightarrow x=\frac{12 \pm \sqrt{120}}{12} \Rightarrow y=\frac{1}{2} \mp \frac{\sqrt{120}}{12} \end{aligned}$ So length of chord

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About this question

This is a previous-year question from JEE Main 2025, covering the Ellipse chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.