JEE Main 2021MathematicsEllipseEasyMCQ

JEE Main 2021 — Ellipse Question with Solution

JEE Main 2021 (16 Mar Shift 2)

Question

If the points of intersection of the ellipse x216+y2 b2=1 and the circle x2+y2=4 b, b>4 lie on the curve y2=3x2, then b is equal to :

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Show full solutionCorrect option: A
Correct answer
A12

Step-by-step explanation

y2=3x2 and x2+y2=4b

Solving both the equations we get, 

x2=b

As x216+y2b2=1

⇒x216+3x2b2=1

⇒b16+3b=1

⇒b2-16b+48=0

⇒b-12b-4=0

⇒b=12 ∵b>4

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About this question

This is a previous-year question from JEE Main 2021, covering the Ellipse chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.