JEE Main 2020 — Ellipse Question with Solution
From: JEE Main 2020 (Online) 8th January Morning Slot
Question
Let the line y = mx and the ellipse 2x2 + y2 = 1
intersect at a ponit P in the first quadrant. If the
normal to this ellipse at P meets the co-ordinate axes at and (0, ), then is equal
to :
Choose an option
Show full solutionCorrect option: A
Correct answer
A
Step-by-step explanation
Let P be (x1
, y1)
Equation of normal at P is
It passes through
x1 =
Also using 2 + = 1
= 1 -
y1 =
(0, ) is on the normal.
So 0 - =
=
Equation of normal at P is
It passes through
x1 =
Also using 2 + = 1
= 1 -
y1 =
(0, ) is on the normal.
So 0 - =
=
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This is a previous-year question from JEE Main 2020, covering the Ellipse chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.