JEE Main 2020MathematicsFunctionsEasyMCQ

JEE Main 2020 — Functions Question with Solution

JEE Main 2020 (04 Sep Shift 2)

Question

 The minimum value of 2sinx+2cosx is :

Choose an option

Show full solutionCorrect option: D
Correct answer
D21-12

Step-by-step explanation

Using A.M≥G.M.

2sinx+2cosx2≥2sinx·2cosx

⇒2sinx+2cosx≥21+sinx+cosx2

Now    -2≤sinx+cosx≤2

So minimum value of 

2sinx+2cosx=21+-22=21-12  

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About this question

This is a previous-year question from JEE Main 2020, covering the Functions chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.