JEE Main 2019MathematicsFunctionsMediumMCQ

JEE Main 2019 — Functions Question with Solution

JEE Main 2019 (12 Apr Shift 1)

Question

For x ϵ (0,32), let fx=x,gx=tanx and hx=1-x21+x2 . If ϕx=(hof)og)(x), then ϕ π3 is equal to:

Choose an option

Show full solutionCorrect option: D
Correct answer
Dtan⁡11π12

Step-by-step explanation

fx=x

gx=tanx

 hx=1-x21+x2
fogx=tanx
hofogx=htanx

=1-tanx1+tanx=tanπ4-x
ϕx=tanπ4-x
ϕπ3=tanπ4-π3

=tan-π12=-tanπ12

=tanπ-π12=tan11π12

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About this question

This is a previous-year question from JEE Main 2019, covering the Functions chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.