JEE Main 2020MathematicsHyperbolaMediumMCQ

JEE Main 2020 — Hyperbola Question with Solution

JEE Main 2020 (09 Jan Shift 1)

Question

If e1 and e2 are the eccentricities of the ellipse x218+y24=1 and the hyperbola x29-y24=1 respectively and e1,e2 is a point on the ellipse 15x2+3y2=k , then the value of k is equal to

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Show full solutionCorrect option: A
Correct answer
A16

Step-by-step explanation

e1=1-418=79=73
e1=1+49=139=133

Also, 
15e12+3e22=k⇒k=1579+3139
∴k=16

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About this question

This is a previous-year question from JEE Main 2020, covering the Hyperbola chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.