JEE Main 2020 — Hyperbola Question with Solution
From: JEE Main 2020 (Online) 9th January Morning Slot
Question
If e1 and e2 are the eccentricities of the ellipse,
and the hyperbola, respectively and (e1, e2) is a point on the ellipse,
15x2 + 3y2 = k, then k is equal to :
Choose an option
Show full solutionCorrect option: B
Correct answer
B16
Step-by-step explanation
e1 = =
e1 = =
(e1, e2 ) lies on 15x2 + 3y2 = k
= k
k = 16
e1 = =
(e1, e2 ) lies on 15x2 + 3y2 = k
= k
k = 16
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