JEE Main 2018 — Hyperbola Question with Solution
From: JEE Main 2018 (Online) 16th April Morning Slot
Question
The locus of the point of intersection of the lines, and (k is any non-zero real parameter), is :
Choose an option
Show full solutionCorrect option: D
Correct answer
Da hyperbola with length of its transverse axis
Step-by-step explanation
Here, lines are :
y + 4 = 0
(i)
and
Put the value of y from (i) in (ii) we get;
2kx + 4(k2 1) = 0
x = , y =
length of transverse axis
2a = 2 4 = 8
Hence, the locus is a hyperbola with length of its transverse axis equal to 8
y + 4 = 0
(i)
and
Put the value of y from (i) in (ii) we get;
2kx + 4(k2 1) = 0
x = , y =
length of transverse axis
2a = 2 4 = 8
Hence, the locus is a hyperbola with length of its transverse axis equal to 8
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