JEE Main 2024MathematicsIndefinite IntegrationMediumMCQ

JEE Main 2024Indefinite Integration Question with Solution

JEE Main 2024 (06 Apr Shift 2)

Question

If constant, then the maximum value of , is :

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Show full solutionCorrect option: A
Correct answer
A

Step-by-step explanation

$\begin{aligned} & \int \frac{\sec ^2 x d x}{a^2 \tan ^2 x+b^2} \\ & \text { let } \tan x=t \\ & \sec ^2 d x=d t \\ & \int \frac{d t}{a^2 t^2+b^2} \\ & \frac{1}{a^2} \int \frac{d t}{t^2+\left(\frac{b}{a}\right)^2} \\ & \frac{1}{a^2} \frac{1}{\frac{b}{a}} \tan ^{-1}\left(\frac{t}{b} a\right)+c \\ & \frac{1}{a b} \tan ^{-1}\left(\frac{\alpha}{b} \tan x\right)+c \end{aligned}$ on comparing $\begin{aligned} & a b=12 \\ & a=6, b=2 \end{aligned}$ maximum value of

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About this question

This is a previous-year question from JEE Main 2024, covering the Indefinite Integration chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.