JEE Main 2019MathematicsIndefinite IntegrationMediumMCQ

JEE Main 2019 — Indefinite Integration Question with Solution

JEE Main 2019 (10 Jan Shift 2)

Question

If ∫x5e-4x3dx=148e-4x3fx+C, where C is a constant of integration, then fx is equal to

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Show full solutionCorrect option: A
Correct answer
A-4x3-1

Step-by-step explanation

We have, I=∫x5e-4x3dx 

Let, -4x3=t⇒-12x2dx=dt

⇒I=∫-t4et-dt12=148∫tetdt

=148tet-∫etdt=t-1et48+C=-4x3-1e-4x348+C, 
where C is the constant of integration.

Hence, fx=-4x3-1

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About this question

This is a previous-year question from JEE Main 2019, covering the Indefinite Integration chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.