JEE Main 2022MathematicsInverse Trigonometric FunctionsEasyNumerical

JEE Main 2022 — Inverse Trigonometric Functions Question with Solution

JEE Main 2022 (29 Jun Shift 1)

Question

50tan3tan-112+2cos-115+42tan12tan-122 is equal to ______.

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Show full solutionCorrect answer: 29
Correct answer
29

Step-by-step explanation

Let S=50tan3tan-112+2cos-115+42tan12tan-122

=50tantan-112+2tan-112+tan-12+42tan12tan-122

Let 12tan-122=α⇒tan2α=22

Now 2tanα1-tan2α=22

Solving we get, tanα=12

SoS=50tantan-112+2·π2+42×12

=50tantan-112+4

=25+4=29

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About this question

This is a previous-year question from JEE Main 2022, covering the Inverse Trigonometric Functions chapter of Mathematics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.